Optimal. Leaf size=70 \[ -\frac{1}{2} \text{PolyLog}(2,-a x)+\frac{1}{2} \text{PolyLog}(2,a x)+\frac{a^3 x^3}{12}+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-a^2 x^2 \tanh ^{-1}(a x)-\frac{3 a x}{4}+\frac{3}{4} \tanh ^{-1}(a x) \]
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Rubi [A] time = 0.0974804, antiderivative size = 70, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {6012, 5912, 5916, 321, 206, 302} \[ -\frac{1}{2} \text{PolyLog}(2,-a x)+\frac{1}{2} \text{PolyLog}(2,a x)+\frac{a^3 x^3}{12}+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-a^2 x^2 \tanh ^{-1}(a x)-\frac{3 a x}{4}+\frac{3}{4} \tanh ^{-1}(a x) \]
Antiderivative was successfully verified.
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Rule 6012
Rule 5912
Rule 5916
Rule 321
Rule 206
Rule 302
Rubi steps
\begin{align*} \int \frac{\left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{x} \, dx &=\int \left (\frac{\tanh ^{-1}(a x)}{x}-2 a^2 x \tanh ^{-1}(a x)+a^4 x^3 \tanh ^{-1}(a x)\right ) \, dx\\ &=-\left (\left (2 a^2\right ) \int x \tanh ^{-1}(a x) \, dx\right )+a^4 \int x^3 \tanh ^{-1}(a x) \, dx+\int \frac{\tanh ^{-1}(a x)}{x} \, dx\\ &=-a^2 x^2 \tanh ^{-1}(a x)+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-\frac{\text{Li}_2(-a x)}{2}+\frac{\text{Li}_2(a x)}{2}+a^3 \int \frac{x^2}{1-a^2 x^2} \, dx-\frac{1}{4} a^5 \int \frac{x^4}{1-a^2 x^2} \, dx\\ &=-a x-a^2 x^2 \tanh ^{-1}(a x)+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-\frac{\text{Li}_2(-a x)}{2}+\frac{\text{Li}_2(a x)}{2}+a \int \frac{1}{1-a^2 x^2} \, dx-\frac{1}{4} a^5 \int \left (-\frac{1}{a^4}-\frac{x^2}{a^2}+\frac{1}{a^4 \left (1-a^2 x^2\right )}\right ) \, dx\\ &=-\frac{3 a x}{4}+\frac{a^3 x^3}{12}+\tanh ^{-1}(a x)-a^2 x^2 \tanh ^{-1}(a x)+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-\frac{\text{Li}_2(-a x)}{2}+\frac{\text{Li}_2(a x)}{2}-\frac{1}{4} a \int \frac{1}{1-a^2 x^2} \, dx\\ &=-\frac{3 a x}{4}+\frac{a^3 x^3}{12}+\frac{3}{4} \tanh ^{-1}(a x)-a^2 x^2 \tanh ^{-1}(a x)+\frac{1}{4} a^4 x^4 \tanh ^{-1}(a x)-\frac{\text{Li}_2(-a x)}{2}+\frac{\text{Li}_2(a x)}{2}\\ \end{align*}
Mathematica [A] time = 0.0727434, size = 73, normalized size = 1.04 \[ \frac{1}{24} \left (-12 \text{PolyLog}(2,-a x)+12 \text{PolyLog}(2,a x)+2 a^3 x^3+6 a^4 x^4 \tanh ^{-1}(a x)-24 a^2 x^2 \tanh ^{-1}(a x)-18 a x-9 \log (1-a x)+9 \log (a x+1)\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.039, size = 89, normalized size = 1.3 \begin{align*}{\frac{{a}^{4}{x}^{4}{\it Artanh} \left ( ax \right ) }{4}}-{a}^{2}{x}^{2}{\it Artanh} \left ( ax \right ) +{\it Artanh} \left ( ax \right ) \ln \left ( ax \right ) -{\frac{{\it dilog} \left ( ax \right ) }{2}}-{\frac{{\it dilog} \left ( ax+1 \right ) }{2}}-{\frac{\ln \left ( ax \right ) \ln \left ( ax+1 \right ) }{2}}+{\frac{{x}^{3}{a}^{3}}{12}}-{\frac{3\,ax}{4}}-{\frac{3\,\ln \left ( ax-1 \right ) }{8}}+{\frac{3\,\ln \left ( ax+1 \right ) }{8}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.955372, size = 143, normalized size = 2.04 \begin{align*} \frac{1}{24} \,{\left (2 \, a^{2} x^{3} - 18 \, x - \frac{12 \,{\left (\log \left (a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (-a x\right )\right )}}{a} + \frac{12 \,{\left (\log \left (-a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (a x\right )\right )}}{a} + \frac{9 \, \log \left (a x + 1\right )}{a} - \frac{9 \, \log \left (a x - 1\right )}{a}\right )} a + \frac{1}{4} \,{\left (a^{4} x^{4} - 4 \, a^{2} x^{2} + 2 \, \log \left (x^{2}\right )\right )} \operatorname{artanh}\left (a x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \operatorname{artanh}\left (a x\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a x - 1\right )^{2} \left (a x + 1\right )^{2} \operatorname{atanh}{\left (a x \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a^{2} x^{2} - 1\right )}^{2} \operatorname{artanh}\left (a x\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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